---

Sveiki, taigi noriu pasiklausti pas jus kaip reikia teisingai padaryti nauja puslpai su 6ituo kodu.:

echo "<table width='100%'>
<tr>
<td width='33%'>";
openside("Naujausia muzika");
echo "<div class='side-label'><b></b></div>\n";
$result = dbquery("SELECT * FROM ".$db_prefix."downloads ORDER BY download_datestamp DESC LIMIT 100");
if (dbrows($result) != 0) {
echo "<table width='100%' cellpadding='0' cellspacing='0'>";
while ($data = dbarray($result)) {
echo "<tr>
<td class='small'>
<img src='".THEME."images/bullet.gif'>
<a href='".BASEDIR."downloads.php?cat_id=".$data['download_cat']."&download_id=".$data['download_id']."' title='".$data['download_title']."' class='side'>".trimlink($data['download_title'], 40)."</a>
</td>
<td align='right'>".$data['download_count']."</td>
</tr>";
}
echo "</table>";
} else {
echo "<div style='text-align:center'>".$locale['004']."</div>\n";
}
echo "";

@ia kodas top 100. o man reikia padaryti kad butu naujas puslpais pvd: oky.lt/naujiausiamuzika.php. a2i8 +11.