Parašė _Tomas· 2008 Rugs. 27 19:09:45
#1
Įsidėjau funkcija iš chipo straipsnio - Reklama forume - Pasidariau, kad butu 5 ir 10 poste bet dabar iškilo problema tokia:
Parse error: syntax error, unexpected '(' in /home/useris/adresas.lt/forum/viewthread.php on line 120
120 eilutė:
if(dbcount("(*)", "money_banners", "tipas='0'") > 0){
Visas kodas:
if ($rows != 0) {
$result = dbquery(
\"SELECT p.*, fa.attach_id, fa.attach_name, fa.attach_ext, fa.attach_size, u.*, u2.user_name AS edit_name FROM \".$db_prefix.\"posts p
LEFT JOIN \".$db_prefix.\"forum_attachments fa USING(post_id)
LEFT JOIN \".$db_prefix.\"users u ON p.post_author = u.user_id
LEFT JOIN \".$db_prefix.\"users u2 ON p.post_edituser = u2.user_id AND post_edituser > \'0\'
WHERE p.thread_id=\'$thread_id\' ORDER BY post_datestamp LIMIT $rowstart,$posts_per_page\"
);
$numrows = dbrows($result);
$postai = \'0\';
while ($data = dbarray($result)) {
if ($postai == '5' OR $postai == '10') { echo \"<tr><td height=\'5\' colspan=\'2\'></td></tr><tr style=\'margin-top:5px\'><td class=\'tbl2\' valign=\'top\' style=\'margin-top:5px\'>Reklama</td><td style=\'margin-top:5px\' class=\'tbl1\' align=\'center\'>\";
if(dbcount("(*)", "money_banners", "tipas='0'") > 0){
$sql = dbquery("SELECT * FROM ".$db_prefix."money_banners WHERE `parodymai` = `kiekis` and tipas='0' ");
while ($baneris = dbarray($sql)){
unlink(INFUSIONS."pinigu_sistema/banners/468x60/".$baneris[imgas]);
dbquery("DELETE FROM ".$db_prefix."money_banners WHERE id = '".$baneris[id]."' and tipas='0'");
}
$sql = dbquery("SELECT * FROM ".$db_prefix."money_banners WHERE tipas='0' order by rand() LIMIT 3 ");
while ($baneris = dbarray($sql)){
echo "<center><a href='".stripinput(htmlspecialchars($baneris[adresas]))."'><img src='".INFUSIONS."pinigu_sistema/banners/468x60/".$baneris[imgas]."' border='0'></a></center>";
$result = dbquery("UPDATE ".$db_prefix."money_banners SET `parodymai` = `parodymai`+ 1 WHERE id=".$baneris[id]."");
}
}else{
echo "<center><a href='".INFUSIONS."pinigu_sistema/banners468.php'><img src='".INFUSIONS."pinigu_sistema/banners/reklama468.png' border='0'></a></center>";
}
echo\"</td></tr>\"; }
$postai++;
$message = $data[\'post_message\'];
if ($data[\'post_showsig\']) { $message = $message.\"\\n\\n<hr>\".$data[\'user_sig\']; }
if ($data[\'post_smileys\']) { $message = parsesmileys($message); }
$message = parseubb($message);
$message = nl2br($message);
$message = linkas($message);
Parašė ramon· 2008 Rugs. 27 20:09:40
#4
Pirma syki matau toki koda:
echo\"</td></tr>\"; }
$postai++;
$message = $data[\'post_message\'];
if ($data[\'post_showsig\']) { $message = $message.\"\\n\\n<hr>\".$data[\'user_sig\']; }
if ($data[\'post_smileys\']) { $message = parsesmileys($message); }
Parašė ramon· 2008 Rugs. 27 21:09:46
#6
Cia debilizmas ne kodas iprastai \ rashomas tik td kai nori rasyt koki
html koda t.y. kur yra duoble kabutes t.y.: " ir rasoma taip: \" o cia tai vopse debiliskas rasimas...
O del syntax`es kai yra rasoma eilute kurioi yra klaida tai ne visada buna butent toi pacioi eilutei kaip buvo parasita error`e arba kartais buna taip kad is vis ne siame faile arba tame kode.